Exam Revision

Linear Motion

Distinguish between scalar and vector quantities, and add and subtract vectors in one dimension
  • Scalar quantities have a magnitude, Vectors have both direction and magnitude
    • Scalar - distance, e.g. 4.57m4.57m
    • Vector - displacement, e.g. 4.57m South4.57m \space South
  • Adding and subtracting is as it is in maths.
    • Subtract the negative e.g. *What is the change in velocity of Bongleshnout's Scooter as he turns a corner if he approaches it at 18.7msβˆ’118.7ms^{-1} west and exits it at 16.6msβˆ’116.6ms^{-1} north?
      • Remember: Ξ”v=vfβˆ’vi=vf+(βˆ’vi)\Delta v=v_{f}-v_{i}=v_f+(-v_i)
      • As such, this would be 16.6msβˆ’116.6ms^{-1} north + 18.7msβˆ’118.7ms^{-1} east
      • Work from there.
Uniformly accelerated motion is described in terms of relationships between measurable scalar and vector quantities, including displacement, speed, velocity and acceleration β€”this includes applying SUVAT
  • The quantities:
    • Displacement is a vector mm
    • Speed is a scalar m sβˆ’1m \space s ^{-1}
    • Velocity is a vector m sβˆ’1m \space s ^{-1}
    • Acceleration is a vector m sβˆ’2m \space s ^{-2}
  • Remember, simultaneous may have to be done between the SUVATs
Representations, including graphs, vectors, and equations of motion, can be used qualitatively and quantitatively to describe and predict linear motion
  • N.B. m/s to km/h is multiplication by 3.6, and vice versa.
Graphs
  • Velocity-Time
    • Derivative is acceleration
    • Integral is displacement
  • Acceleration-Time
    • Derivative is **JERK
    • Integral is change in velocity
Equations
  • When considering maximum height problems, there will exist a velocity 00
  • On inclined planes, use the equation g sin⁑(ΞΈ)g \space \sin(\theta)
    • Remember, mass has no impact on acceleration (though it does on friction, but on inclined plane questions friction is usually discounted)
Vertical motion is analysed by assuming the acceleration due to gravity is constant near Earth’s surface
  • The value aa for gravity is 9.8m sβˆ’29.8m \space s^{-2}
Newton’s three Laws of Motion describe the relationship between the force or forces acting on an object, modelled as a point mass, and the motion of the object due to the application of the force or forces
  • Force (FF) is measured in NN; it is a vector quantity
  • Laws
    1. An object will maintain constant velocity unless an unbalanced, external force acts on it - informally, 'no force, no acceleration'
      • Inertia is considered to be the resistance to a change in motion of an object.
      • It is directly related to momentum.
      • Due to inertia, an object will continue with its motion unless a net force acts on the object.
    2. F=maF=ma
      • i.e. 'The acceleration of an object is directly proportional to the net force on the object and inversely proportional to the mass of the object'
      • F=ma, βˆ΄F=Ξ”pΞ”tF=ma, \space \therefore F=\frac{\Delta p}{\Delta t}
    3. For every action (force), there is an equal and opposite reaction (force).
Free body diagrams show the forces and net force acting on objects, from descriptions of real-life situations involving forces acting in one or two dimensions
  • This is an experience thing, just know how to do it.
Momentum is a property of moving objects; it is conserved in a closed system and may be transferred from one object to another when a force acts over a time interval
  • Momentum is conserved in a closed system and a property of moving objects. It is a vector quantity
  • p=mvp=mv
    • mass x velocity
    • measured by kg m sβˆ’1kg \space m\space s^{-1}
  • Momentum is conserved in interactions between objects and thus βˆ‘P\sum\limits P before = βˆ‘P\sum\limits P after.
    • Since it involves many vectors, to get direction easily, assign a negative and a positive.
  • Change in momentum is impulse
    • =mvβˆ’mu=m(vβˆ’u)=mΞ”v=mv-mu=m(v-u)=m\Delta v
    • Unit is NsN s (Newton-Seconds) and is a **vector
Energy is conserved in isolated systems and is transferred from one object to another when a force is applied over a distance; this causes work to be done and changes the kinetic (Ek) and/or potential (Ep) energy of objects
  • Energy is the capacity to cause a change
  • Kinetic and Potential energy are both types of Mechanical energy, measures in Joules as a Scalar
    • Any moving object has kinetic energy.
      • =12mv2=\frac{1}{2}mv^2
    • Potential energy is the energy of objects relative to one another or in fields.
      • Gravitational potential Energy (GPE) is mghmgh
  • Work is the transferring or transforming of energy on an object.
    • W=FsW=Fs or W=Fscos⁑θW=Fs\cos \theta where ΞΈ\theta is the angle between FF and ss
      • or =12mv2βˆ’12mu2=\frac{1}{2}mv^2-\frac{1}{2}mu^2
    • It is measured in Joules as a Scalar
    • If a force is applied on an object but it does not move (s=0s=0), then no work is done on it.
    • On a force-displacement graph, work is the integral.
  • Total Mechanical Energy is the sum of kinetic and GPE energies
Collisions may be elastic and inelastic; kinetic energy is conserved in elastic collisions
  • Literally what the objective says.
Power is the rate of doing work or transferring energy
  • Measures in Watts as a Scalar

Car Crashes

Seatbelts
  • Due to Newton's first law, if a car suddenly decelerates, then the occupants will stay in motion, flying out the window or hitting it (bad). Seatbelts oppose the inertia of occupants' bodies.
Airbag
  • As the occupants move forward due to inertia, airbags increase the time that the force is applied. Due to this, impulse is drawn out over a greater period of time and force is minimized.
Crumple zones, helmets and safety barriers
  • Same as airbags. Increase time, decreasing force.

Waves

Questions

(from pearson)

  1. Determine the resultant force when forces of 5.0N5.0N east and 3.0N3.0N north act on a tree.
  2. Determine the change in velocity of a ball as it bounces off a wall. The ball approaches at 7.0m sβˆ’17.0m\space s^{-1} south and rebounds at 6.0m sβˆ’16.0m \space s^{-1} east. Make sure to include an appropriate vector diagram.
  3. Bob is applying a force of 15.0N15.0N to a sled on a frictionless surface, using a handle that is angled 50Β°50\degree to the ground. The sled weighs 7.45kg7.45kg. What is its acceleration?
  4. A golf ball is dropped onto a concrete floor and strikes the floor at 9.0m sβˆ’19.0m \space s^{-1}. It then rebounds at 7.00m sβˆ’17.00m \space s^{-1}. The contact time with the floor is 35ms35ms. What is the average acceleration of the ball during its contact with the floor?
  5. A cyclist takes 4.00s4.00s to slow down at βˆ’3.00m sβˆ’2-3.00m \space s^{-2} and completely stop. Calculate the initial velocity of the cyclist.
  6. A 1200kg1200kg wrecking ball is moving at 2.50m sβˆ’12.50m \space s^{-1} north towards a 1500kg1500kg wrecking ball moving at 4.00m sβˆ’14.00m \space s^{-1} south. Calculate the final velocity of the more massive wrecking ball if the other ball rebounds at 3.50m sβˆ’13.50m \space s^{-1} south.
  7. A 65.0g65.0g pool ball is moving at 0.250m sβˆ’10.250m \space s^{-1} south towards a cushion and bounces off at 0.200m sβˆ’10.200 m \space s^{-1} east. Calculate the impulse on the ball during the change in velocity.
  8. Calculate the final velocity of a 307g307g fish that accelerates for 5.20s5.20s from rest due to a force of 0.250N0.250N left.
  9. A student drops a 56.0g56.0g egg onto a table from a height of 60cm60 cm. Just before it hits the table, the velocity of the egg is 3.43m sβˆ’13.43m\space s^{βˆ’1} down. The egg’s final velocity is zero as it smashes on the table. The time it takes for the egg to change its velocity to zero is 3.55ms3.55ms.
  10. A car with a mass of 1200kg1200kg is travelling at 90km hβˆ’190km\space h^{βˆ’1}. Calculate its kinetic energy at this speed.
  11. As a bus with a mass of 1010 tonnes approaches a school it slows from 60km hβˆ’160km\space h^{βˆ’1} to 40km hβˆ’140km\space h^{βˆ’1}. Calculate, to 2 sig figs, the work done by the brakes on the bus and the average force applied by the truck's brakes if it travels 40m40m over deceleration.
  12. A 200g200g snooker ball with initial velocity 9.0m sβˆ’19.0m\space s^{βˆ’1} to the right collides with a stationary snooker ball of mass 100g100g. After the collision, both balls are moving to the right and the 200g200g ball has a speed of 3.0m sβˆ’13.0m\space s^{βˆ’1}. Show calculations to test whether or not the collision is inelastic.
  13. A father picks up his baby from its bed. The baby has a mass of 6.0kg6.0kg and the mattress of the bed is 70cm70cm above the ground. When the father holds the baby in his arms, it is 125cm125cm off the ground. Calculate the increase in gravitational potential energy of the baby, taking gg as 9.80N kgβˆ’19.80N\space kg^{βˆ’1} and giving your answer correct to two signifcant fgures.
  14. An arrow with a mass of 35g35g is fired into the air at 80m sβˆ’180m\space s^{βˆ’1} from a height of 1.4m1.4m. Calculate the speed of the arrow when it has reached a height of 30m30m.
  15. An 800.0kg800.0kg racecar’s engine is capable of generating 120kW120kW of power. How long does it take the car to accelerate from 40.0m sβˆ’140.0m\space s^{βˆ’1} to 55.0m sβˆ’155.0m\space s^{βˆ’1}?